32v^2/2v=128

Solution for 32v^2/2v=128 equation:

32v^2/2v=128

We move all terms to the left:

32v^2/2v-(128)=0


Domain of the equation: 2v!=0

v!=0/2

v!=0

v∈R


We multiply all the terms by the denominator


32v^2-128*2v=0

Wy multiply elements

32v^2-256v=0

a = 32; b = -256; c = 0;
Δ = b2-4ac
Δ = -2562-4·32·0
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-256)-256}{2*32}=\frac{0}{64}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-256)+256}{2*32}=\frac{512}{64}
=8
$